I'm sorry but your theory is not sound...you are talking about only the pressure of the fuel being pushed forward and 1 times gravity so in that sense things would not change no matter the size of the line but you have to take into account the mass of the fuel, the fact that it is parallel to the ground as well as the acceleration forces are greater than 1 times gravity. I follow where you are coming from but if you follow your logic and read this information about centrifugal pumps in the link to follow, the issue at hand is that fuel pumps are only rated up to a certain head pressure but they do have a stall point. The larger fuel line is going to have more fuel in it which then will have more mass and as acceleration increases that mass will act as additional pressure/force back against the centrifugal pump and at some point it will exceed the "head of the pump" and stall out the fluid flow. Also, after reading a little more on how the centrifugal pump works, it is creating kinetic energy in the flow of the fuel which is also what is happening when the vehicle is accelerating. If the pump can not overcome that "reverse" kinetic energy which is dependent on the mass of the fuel(larger line has more fuel and overall more mass) and the movement which in this case is the acceleration of the car, then the pump looses that battle.
http://www.engineeringtoolbox.com/centrifugal-pumps-d_54.html
I don't need to look at that link, I "passed" the test regarding pumps 3 times - once to get my Engineering degree and twice to get my Professional Engineering license. And what I have written is not based on a theory, it's based on the Engineering principals involved with fluid dynamics. And fluid dynamics is used to determine the pump characteristics.
Let's discuss fluid dynamics. The total "dynamic head" is the static head, suction head and frictional losses. Suction head is related to feeding the pump so we will assume it is the same for this example.
To determine static head during acceleration, we simply use the highest "g" and calculate the static head based on that (this is called "modeling"). In the case of a car accelerating at 2g, we simply multiply the static "1g" x 2. But the resultant pressure stays the SAME no matter what line size. So yes, acceleration affects the static pressure, but the affect it is the same for all diameter lines. So a line with 1sq-in will have the same static pressure as a 10sq-in line. (I understand the concept is "static head" pressure is counter-intuitive in some ways but the pressures are the same in large and small lines.)
Say we have to move fuel at 10lbs/min. So what happens when we do it in a line with an inside area of 1"sq-in vs. one with 10"sq-in. With the 1"sq-in line I would have to accelerate the fuel to 10x the velocity of the 10" line. (I assume everyone can figure out the math involved to calculate the velocity). So now we have fluid in the small line moving at 10x the velocity as the one in the large line. I hope everyone agrees that the frictional losses are greater for the smaller line.
So now we have a 1"sq-in line and a 10"sq-in line with the same static head but the 1"sq-in line has more friction so it will have the highest "dynamic head" - the most pressure to overcome.
Kinetic energy was mentioned. The formula for kinetic energy is 1/2mv2. Which line has the most kinetic energy? It should be obvious since we're moving the same mass in both cases and the smaller line has 10x the velocity, then it will be have 100x the kinetic energy. So it also take more energy just to accelerate the fuel mass to that flow rate.
Going back to "static pressure head". One quick example to demonstrate the concept. Take small pond and a large lake, both very deep. The small pond would be like a small diameter line, the large lake like a large diameter line. Water in each is "accelerating" at 1g.
If a diver goes down 100ft, he will experience the same pressure in both bodies of water.